Start studying Chapter 6 The Little Man Computer. Learn vocabulary, terms, and more with flashcards, games, and other study tools. Jump to Using Numeric Instruction Codes - It can be programmed in machine code (albeit in decimal rather than binary) or assembly code. The LMC model is based on the concept of a little man shut in a closed mail room (analogous to a computer in this scenario).

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0 => 0 1 => 1 2 => 1 3 => 2 4 => 3. 16 => 987- values bigger than 17 dont have to give the right output (so dont worry about overflow).

- Winner is, who ever can achieve this with the fewest lines of code. Pro tip: Use a external text editor for writing code and import it into the “Program” list, then press the green flag to update. Its quite hard to change code with the “built in” editor. My best mark is 19 lines of code, but i think everything below 25 is quite good.

PS: Feel free to post your own challenge here! EDIT: Wikipedia article linked EDIT2: Protip Last edited by MartinBraendli (Oct. 17, 2015 02:25:37). MartinBraendli wrote: MegaApuTurkUltra wrote:Yay, 27 25 22 lines Congrats! Happy to see someone accepted the challenge. I've never programmed in Assembly before, but I like the hunt for those “wasted lines”. 30-40 years ago this must have been a big part of a programmers job.

I think 18 lines might be possible somehow, but if someone manages to get 17 i'd be really surprised. When I reached 19 i googled for other solutions and i couldnt find any with less than 21 lines (and the one with 21 was a bit flawed). Generic usb hub driver for windows 8. I've never tried assembly before so I'm not going to attempt to shorten mine any more.

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I've already removed 5 lines:P I'll leave further golfing to the assembly pros. INP SUB ONE SUB ONE START STA COUNTER LDA CURRENT ADD OLD STA CURRENT SUB OLD STA OLD LDA COUNTER SUB ONE BRP START LDA CURRENT OUT COUNTER DAT OLD DAT 0 CURRENT DAT 1 ONE DAT 1 19 18 lines This uses a dirty hack that probably isn't portable (add a HLT after OUT to make it valid). Let me explain: For the input case 1, the program goes through the entire thing and prints 1, then goes over the DAT spaces which are all 1 until it reaches space 19 which is a 0 since the program doesn't use it. Then, it halts For the input case 1, the program goes over the entire thing and prints 1, then it goes over the DAT space for COUNTER which is 0 at this point, so it halts. For all other valid input cases, the program loops as necessary until COUNTER is 0 and then uses COUNTER as a HLT.

Now the hacky case is where input is 1, because the interpreter has to go over a bunch of unknown commands. But, it works in chooper100's interpreter so I'm going to assume it's valid ————————————– If printing unnecessary output is allowed, here's a 17 16 line version that uses the same dirty hack.

INP LDA N LOOP OUT ADD ONE BRA LOOP N DAT 0 ONE DAT 1For any valid input, this WILL output the corresponding fibonacci number. However, it will also output every other natural number and wont even terminate. But without the 1-IN/1-OUT rule, this would (technically) be a valid solution.

EDIT: Anyway, thank you for your participating. I enjoyed seeing your code progress and finally beat mine. EDIT2: If you write machine code instead of assembly, you could bring it down to legit 16 lines, since you wouldnt have to initialize FIB2/ OLD since its 0 anyway. Just use 316 and 516 to store/load.